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## Homework Statement

The two voltmeters have very large resistance, the 3 ampere meter have resistance of ##0.5\Omega## each one.

##V_1## show twice as much voltage as ##V_2##, ##A_1## shows ##0.4A## and ##A_2=A_3=0A##

a. Find ##R_2##

b. Find the internal resistance of the battery

## Homework Equations

KVL and KCL

Thevenin and Norton

Pi-T

## The Attempt at a Solution

[/B]

I did not saw a reason to use Thevenin or Norton, because ##A_2=A_3=0A## I can look at the circuit like this:

And to start with KVL and KCL:

1) ##0.4=I_2+I_3##

2) ##1.6-0.4r-R_1*I_2-5I_2-R_2*I_2=0##

3) ##1.6-0.4r-2I_3-2.5I_3-R_3*I_3=0##

4) ##2V_2=V1\rightarrow 1.6-0.4r=5I_3##

5) ##A_2=0A## so there is also not voltage so ##R_1*I_2+2*I_3=0##

6)##A_3=0A## so there is also not voltage so ##R_2*I_2+R_3*I_3=0##

But I am left with unknowns